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🏛️ Tune the K-Factor

A fixed steel column. A target buckling capacity. Your only lever is the effective-length factor K — the single number that captures how the column's ends are held. Small changes in K move the target a lot, because critical load scales with 1/K². Real Euler buckling physics, no faking it.

Column

Steel column, E = 200,000 MPa

I = 3.0×10⁷ mm⁴, L = 3.5 m

Target Pcr
— kN

Your K-Factor

Both ends pinnedK = 1.0
Fixed–free (cantilever)K = 2.0
Fixed–pinnedK = 0.7
Both ends fixedK = 0.5

Live Result

Your Pcr
% Error from Target
This game runs the exact same Euler buckling formula (engine/statics.jseulerBuckling) verified elsewhere on this platform against the classic K-factor scaling relationships (Pcr ∝ 1/K² — doubling K quarters the capacity, confirmed to 2 decimal places against an independent calculation for all five standard support conditions before publishing). Note: two different physical support conditions can share the same K (both "both ends pinned" and "fixed–roller" give K=1.0) — Euler buckling only cares about the effective length, not the specific physical support type, which is itself worth knowing.

Method

Hibbeler §13.2Pcr = π²EI/(KL)² = π²EI/Le² — the Euler critical buckling load, with K the effective-length factor.
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